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4x^2-94x+377=0
a = 4; b = -94; c = +377;
Δ = b2-4ac
Δ = -942-4·4·377
Δ = 2804
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2804}=\sqrt{4*701}=\sqrt{4}*\sqrt{701}=2\sqrt{701}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-94)-2\sqrt{701}}{2*4}=\frac{94-2\sqrt{701}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-94)+2\sqrt{701}}{2*4}=\frac{94+2\sqrt{701}}{8} $
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